Calculate the enthalpy of the reaction N2 + 3H2 2NH3, where the enthalpy of N, is 30.16 kcal, the
enthalpy of H, is 20.82 kcal, and the enthalpy of NH3 is 29.01 kcal.

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2

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explanation:

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