Conceptual Checkpoint 21.23 When 2,6-heptanedione is heated in the presence of aqueous sodium hydroxide, a condensation product with a six-membered ring is obtained. Draw the product and show a mechanism for its formation. For the mechanism, draw the curved arrows as needed. Include lone pairs and charges in your answer. Do not draw out any hydrogen explicitly in your products. Do not use abbreviations such as Me or Ph.

See explanation below

Explanation:

In this case, the mechanism of reaction is attached in the picture below.

The first step, the OH- substract an atom of hydrogen of the molecule, the most acidic, which would be the terminals. When that happens, the negative charge goes down to form a double bond C = C and the carbonyle opens up. The next step the carbonyle group goes down again and the double bond C = C goes to the carbonyle group if the same molecule. This is the condensation. In this step, the molecule close, and a ring is formed. Then, because we are heating, the OH- is a very good leaving group in condensations, so it forms a double bond at the final.

See mechanism below

3

explanation:

the answer is 0.8m.

by: nicholas