Perform the following calculations then use the Molarity PhET simulation to check answers.

What is the molarity of a 0.400 L solution containing 0.700 moles of Cobalt (II) Chloride?

How many moles of Potassium Permanganate are in 350.0 mL of 0.50 M KMnO4 (aq)?

How many liters of 3.0 M Potassium Chromate solution will contain 2.0 moles of K2CrO4 ?

a = 1.75M

b = 0.175moles

c = 0.67L

Explanation:

Molarity of a substance is the number of moles present in 1L of a solution.

a). 0.7 moles is present in 0.4L

X moles is present in 1L

0.7moles = 0.4L

X moles = 1L

X = 1.75M

The molarity of the solution is 1.75M

b). 0.5moles is present in 1L

X moles will be present in 0.35L

X = (0.5 × 0.35) / 1 = 0.175moles

0.175 moles will be present in 0.35L of the solution

c). 3.0moles is present in 1L

2 moles will be present in how many L

3.0moles = 1L

2.0moles = xL

X = (2.0 / 3.0) / 1

X = 0.67L

2 moles is present in 0.67L of the solution

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error

it is b that is the answer.