2. A sample of gas has a pressure of 861.05 kPa at a temperature of 25°C. What temperature is required to
increase the pressure to 1985.48 kPa?

The final temperature is 414.34 degrees Celsius.

Explanation:

Gay-Lussac's law gives the relation between pressure and temperature. It states that at constant volume, pressure is directly proportional to the temperature of the gas.

We have,

Initial pressure,

Initial temperature,

Final pressure,

It is required to find new temperature, using Gay-Lussac's law as:

or

So, the final temperature is 414.34 degrees Celsius.

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.