How many grams of Na2SO4 are required to make 0.30 L of 0.500 M Na2SO4?

21.3 g of are required to make 0.30 L of 0.500 M .

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

where,

n = moles of solute

= volume of solution in L

moles of =

Now put all the given values in the formula of molality, we get

Therefore, 21.3 g of are required to make 0.30 L of 0.500 M .

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