Hydrazine, N2H4 , reacts with dinitrogen tetroxide, N204.

2 N HAO + N20(g) — 4 H20 (1) + 3 N, (g)

When 0.10 mol of hydrazone reacts with 0.10 mole of dinitrogen tetroxide, which of the following
quantities would be consumed or produced?

Select one:
a. 0.05 mol N204
b.0.40 mol H2O
C. 0.39 mol N2
d. 0.10 mol N204

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g