Given the balanced equation representing a redox reaction:

2Al + 3Cu2+ → 2Al3+ + 3Cu

Which statement is true about this reaction?

The given question is incomplete, the complete question is:

Given the balanced equation representing a redox reaction:

2Al + 3Cu2+ --> 2Al3+ + 3Cu

Which statement is true about this reaction?

(1) Each Al loses 2e- and each Cu2+ gains 3e-

(2) Each Al loses 3e- and each Cu2+ gains 2e-

(3) Each Al3+ gains 2e- and each Cu loses 3e-

(4) Each Al3+ gains 3e- and each Cu loses 2e-

The correct answer is option 2, that is, in the given reaction each of Al loses three electrons and each of the Cu^2+ ion acquires two electrons.

Explanation:

To understand the concept, let us suppose that when an atom A loses an electron, it turns into an atom A^1+, and becomes A^2+ when it loses two electrons. On the other hand, when an atom A gains an electron, it turns into A^1- and becomes A^2- when it acquires two electrons.  

Therefore, in the given case, 2Al + 3Cu^2+ --> 2Al^3+ + 3Cu, each of the Al atom turns into Al^3+ when it loses three electrons, and when each of the Cu^2+ ions acquires two electrons, it turns into Cu (Cu^2+ ^2- = Cu).  

yes, water is wet, just as it makes other things wet, it is wet itself, kinda like ice, when ice is in water, the ice makes water cold, and ice is cold, therefore with that example, water is wet