What is the molariity of a 50.0 mL aqueous solution containing 10.0 grams of copper (ll) sulfate, CuSO4

Explanation:

First, we need to convert 50.0 mL to L.

1 mL = 0.001 L

50.0 mL = 0.05 L

Now, we need to find the number of moles of CuSO4 when given 10.0 grams of the compound.

159.609 grams CuSO4 = 1 mol CuSO4

10.0 grams CuSO4 = 0.0627 mol CuSO4

Now, we can plug in this information into the formula.

So, the molarity of copper (II) sulfate is 1.254 when given a 50.0 mL aqueous solution.

answer: at room temperature (roughly 20 degrees c), you can dissolve 203.9 grams (or 200 grams) of sugar in 100 ml of water. as water temperature increases, the amount of sugar that will dissolve increases, up to about 500 grams of sugar in 100 ml water at 100 degrees c.

explanation: