A 25 mL sample of 0.100 M HNO3 completely reacts with NaOH according to this equation:

HNO3(aq) + NaOH (aq) → NaNO3(aq) + H2O(1)

How many moles of HNO3 are in the sample?

2.5x10^–3 mole.

Explanation:

Data obtained from the question include:

Volume of solution = 25mL

Molarity of HNO3 = 0.1M

Mole of HNO3 =..?

First, we'll begin by converting 25mL to L. This can be achieved by doing the following:

1000mL = 1L

Therefore, 25mL = 25/1000 = 0.025L

Now, we can obtain the number of mole of HNO3 present in the solution as follow:

Molarity = mole /Volume

Mole = Molarity x Volume

Mole = 0.1 x 0.025

Mole = 2.5x10^–3 mole.

Therefore, 2.5x10^–3 mole of HNO3 is present in the solution.

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