When k2so4 is separated into its ions, how is it written?

and

Explanation: Potassium is a first group metal with one valence electron and so it has +1 charge. Sulfate ion is a polyatomic ion with -2 charge. The compound potassium sulfate has two potassium ions and one sulfate ion and the below equation shows how the ions are written when the compound is dissociated into its ions.

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o