What is the density (g/L) of NH3 at 105 kpa and 25 C ( 0.721 g/mol)?

PLEASE HELP :) WILL GIVE BRAINLIEST

0.721 g/L

Explanation:

Ideal gas equation ->PV= nRT   ; n= mass (m)/ molar mass (M);

densitiy= mass (m)/ volume (V)

PV= (m/M)*RT  -> PVM= mRT   -> PM/RT= m/V   -> PM/RT=d

We need to put in SI units

105 Kpa= 1.04 atm

25°C= 298 K

d= (1.04 atm * 17 g/ mol)/(0.0821 * 298 K) = 0.721 g/L

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.