2. If 2.50g of sodium hydroxide is being reacted with 4.30g of magnesium chloride, how many grams of magnesium hydroxide would be produced?

how should i go about solving this equation

1.822 g of magnesium hydroxide would be produced.

Explanation:

Balanced reaction:

     Compound                                 Molar mass (g/mol)

         NaOH                                           39.997

                                                    95.211

                                               58.3197

So, 2.50 g of NaOH = mol of NaOH = 0.0625 mol of NaOH

      4.30 g of  = mol of = 0.0452 mol of

According to balanced equation-

2 mol of NaOH produce 1 mol of    

So, 0.0625 mol of NaOH produce mol of NaOH or 0.03125 mol of NaOH

1 mol of produces 1 mol of

So, 0.0452 mol of produce 0.0452 mol of

As least number of moles of are produced from NaOH therefore NaOH is the limiting reagent.

So, amount of would be produced = 0.03125 mol

                                                                           = g

                                                                           = 1.822 g

i just learnt this recently but i need to look through my notes again

a:

by the combination of an unlimited number of elements