How much energy is required to melt a 9.070kg (convert to grams first: 1kg=1000g) bag of ice at 0ºC? Write the formula and write answer with unit.

The energy required to melt 9.070 kg of ice is 3047520 J

Explanation:

The mass, m of the ice = 9.070 kg = 907.0 g

The latent heat of fusion, ° for ice = 3.36×10⁵ J/Kg

Therefore we have the formula for the energy required to melt the mass m equals

Plugging in the values, we have;

ΔH = 3.36 × 10⁵ J/Kg×9.070 kg  = 3047520 J or

ΔH = 3.36 × 10² J/g×9070 g  = 3047520 J

Therefore, the energy required to melt 9.070 kg of ice = 3047520 J.

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.