If 21.4 g of aluminum is reacted with 91.3 g of iron (III) oxide, the products will be aluminum oxide and iron metal. What mass of iron will be produced?

The mass of iron produced is 44.29 grams

Explanation:

Al + FeO3    

Aluminium + Iron III oxide

2Al + F₂O₃ → Al₂O₃ + 2Fe

Molar mass of Al = 26.981539 g/mol

Molar mass of F₂O₃ = 159.69 g/mol

Number of moles of Aluminium = 21.4 g/26.981539 g/mol = 0.7931 moles

Number of moles of F₂O₃ = 91.3 g/159.69 g/mol = 0.572 moles

Hence, 1 mole of Al combines with 1/2 moles of F₂O₃, 0.7931 moles of Al will combine with 0.7931 × 1/2 or 0.3966 moles of F₂O₃ to produce 0.7931 moles of iron

Molar mass of iron = 55.845 g/mol

Therefore the mass of iron produced = Number of moles × Molar mass = 0.7931 × 55.845 = 44.29 grams.

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the answer is na (sodium)