A 440.0 g piece of copper is dropped into 400.0 mL of water at 20.00 °C. The final temperature of the water was measured at 35.80 °C. Calculate the initial temperature of the metal. (SCu = 0.3850 J/gC)

207.50°C

Explanation:

Mass of metal (M1) = 440g

Volume of water = 400mL

Initial temperature of water (T2) = 20°C

Final temperature of the mixture (T3) = 35.80°C

Specific heat capacity of the metal (C1) = 0.3850J/g°C

Specific heat capacity of water = 4.184J/g°C

Density of water = 1g/mL

Temperature of metal (T1) = ?

Heat lost by the metal = Heat gained by the water

Q = MC∇T

Q = heat energy

M = Mass

C = specific heat capacity

∇T = change in temperature

M1C1(T1 - T3) = M2C2(T3 - T2)

M2 = ?

Density = mass / volume

Mass = density * volume

Mass = 1g/mL * 400mL

Mass = 400g

M1C1(T1 - T3) = M2C2(T3 - T2)

400 * 0.3850 (T1 - 35.80) = 400 * 4.184 * (35.80 - 20)

154(T1 - 35.80) = 1673.6 * (15.8)

154T1 - 5513.2 = 26442.88

154T1 = 26442.88 + 5513.2

154T1 = 31956.08

T1 = 31956.08 / 154

T1 = 207.50

The initial temperature of the metal was 207.50°C

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explanation:

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both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .