A mass of 10 kg s −1 of Cu(O3)2 ∙ 6H2O along with 13 kg s −1 of water, both at 25 ℃, are fed to a tank where mixing takes place. The resulting solution passes through a heat exchanger which adjusts its temperature to 25 ℃. What is the rate of heat transfer in the exchanger? • For Cu(O3)2, ΔHf298 o = −302.9 k • For Cu(O3)2 ∙ 6H2O, ΔHf298 o = −2,110.8 k • The heat of solution of 1 mol of Cu(O3)2 in water at 25 ℃ is -47.84 kJ, independent of ñ for values of interest here.

the volume increases

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

answersilicon (si); oxygen (o);