Express the equilibrium constant for the following reaction. 3 CH3Cl(g) + 3/2 Cl2(g) ⇔ 3 CH2Cl2(g) + 3/2 H2(g) Express the equilibrium constant for the following reaction. 3 CH3Cl(g) + 3/2 Cl2(g) ⇔ 3 CH2Cl2(g) + 3/2 H2(g) K = [CH3Cl][Cl2]5[CH2Cl2][H2]5 K = [CH3Cl]3[Cl2]3/2[CH2Cl2]3[H2]3/2 K = [CH3Cl][Cl2][CH2Cl2][H2] K = [CH2Cl2][H2]3[CH3Cl][Cl2]5 K = [CH2Cl2]3[H2]3/2[CH3Cl]3[Cl2]3/2

K = [CH2Cl2]^3 [H2]^3/2 /[CH3Cl]^3 [Cl2]^3/2

Explanation:

Step 1:

We'll begin by writing the balanced equation the reaction. This is given below:

3CH3Cl(g) + 3/2Cl2(g) <=> 3CH2Cl2(g) + 3/2H2(g)

Step 2:

Writing an expression of the equilibrium constant. This is illustrated below:

The equilibrium constant is simply the ratio of the concentration of the products to that of the reactants. The equilibrium expression for the equilibrium constant for the above reaction is given below:

K = [CH2Cl2]^3 [H2]^3/2 /[CH3Cl]^3 [Cl2]^3/2

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of carbon is as shown here in the image.

8 m/s because for him to get the same amount of energy as ray is putting out, bobby, who weighs half as much as ray, needs to run twice as fast.