How many grams of CuO would be required to produce 10.0 moles of
nitrogen gas in the following chemical reaction?
2 NH3(g) + 3 CuO(s) 3 Cu(s) + N2(g) + 3 H2O(g)

2390 CuO

Explanation:

                           2 NH3(g) + 3 CuO(s)  --->  3 Cu(s) + N2(g) + 3 H2O(g)

from reaction                         3 mol                               1 mol

given                                       x mol                               10.0 mol

x = 3*10.0/1 = 30.0 mol

M(CuO) = 63.5 + 16.0 = 79.5 g/mol

m(CuO) = 30.0 mol CuO * 79.5 gCuO/1 mol CuO = 2390 g CuO

in theory, limestone is composed principally of the compound calcium carbonate - caco3, but in reality this compound is deposited in conditions involving a number of other compounds as impurities so it ends up being a mixture of many compounds.

hope this : -)

tony (lordcaos066)

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