525 grams of tin(II) fluoride are dissolved in water to create a solution with a total
volume of 3.50 L. What is the molarity of the solution?

MOLARITY =  0.9554 mol/dm3

Explanation:

525 grams of SnF2 in 3.50 L of wate

To obtain the molarity, calculate the concentration in g/dm3 and then concentration in mol/dm3

Concentration in g/dm3  = 525 g/ 3.50 L

= 525g/ 3.50 dm3

= 150g/dm3 of SnF4

Concnetration in mol/dm3

concentration in mol/dm3 = concentration in g/dm3 / Relative molecular mass of SnF2

RMM of SnF2 = ( 119 + 19*2) = 157 g/mol

= 150g/dm3 / 157g/mol

= 0.9554 mol/dm3 of solution.

The molarity of the solution is therefore 0.9554mol/dm3

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.