Consider the reaction of C6H6 + Br2 →CH5Br + HBr ((equation not balanced)
a. What is the theoretical yield of C6H5Br if 142.1 g of C6Hreacts with 173.0 g of Br2?
What is the limiting reagent?
b. What mass of excess remains?
c. If the actual yield of C6H5Br is 163.6 g, what is the percent yield?

The phase where ice changes directly to gas is called sublimation 

Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.

A. is your answer.  hope this