A 3.88 mol sample of gas has a temperature of 28°C and a pressure of 885 torr. What is its volume?

V = 82.31L

Explanation:

Number of moles (n) = 3.88 moles

Temperature (T) = 28.0°C = (28.0 + 237.15)k = 301.15K

P = 885torr = 1.164atm (convert pressure in torr to atm)

1 atm = 760torr

x atm = 885 torr

X = (885 * 1) / 760

P = 1.164atm.

Volume (V) = ?

R = 0.082J/mol.K

From ideal gas equation,

PV = nRT

P = pressure

V = volume of the gas

n = number of moles

R = idealgas constant

T = temperature

PV = nRT

V = nRT/ P

V = (3.88 * 0.082 * 301.15) / 1.164

V= 82.31L

The volume of the gas is 82.31L

the electrical  conductivity  of asolution  of an electrolyte is measured by determining the resistance of thesolution  between two flat or cylindrical electrodes separated by a fixed distance.

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