What is the minimum total energy released when an electron and its antiparticle (positron) annihilate each other?

Solution:

the minimum total energy released when an electron and its antiparticle (positron) annihilate each other is:-

2 mc^2.    [Mass of electron m and c is the velocity of light.]  

m=1*10^(-30) kg., c =3*10^ 8 m/s  

energy released = 2 *9* 10 ^(-14) j  

1 j =6*10^(18) eV.  

Energy released = 6*18*10^4 eV

                               =104*10^4 eV  

                                 =1.04 MeV.

the answer is true. hope it .

i dont know the answe