Two substances, A and B, which are of equal mass but at different temperatures, come into thermal contact. The specific heat capacity of substance A is three times larger than the specific heat capacity of substance B. Part A Which statement is true of the temperature of the two substances when they reach thermal equilibrium? (Assume no heat loss other than the thermal transfer between the substances.)
A. The final temperature of both substances is closer to the initial temperature of substance A than the initial temperature of substance B.
B. The final temperature of both substances is closer to the initial temperature of substance B than the initial temperature of substance A.
C. The final temperature of both substances is exactly midway between the initial temperatures of substance A and substance B.
D. The final temperature of substance B is greater than the final temperature of substance A.

C. The final temperature of both substances is exactly midway between the initial temperatures of substance A and substance B.

Explanation:

We can assume this problem with letters.

A has an m mass and B has an m mass.

Specific heat of B, is B, and, as the excersise announced, specific heat of A is 3B.

Initial T° of A = Z

Initial T° of B = Y

Assume no heat loss other than the thermal transfer between the substances, so let's apply the calorimetry formula

m . 3B (X - Z) = m . B (X - Y)

Notice, that X will be the final temperature.

We cancel m and B, because they have the same value. We finally got

3 (X - Z) = X - Y

3X - 3Z = X - Y

2X = -Y + 3Z

So final temperature is -Y/2 + 3/2Z

It can not be, that the final temperature of both, A and B are different because they are in thermhal equilibrium

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

→

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.