1.How many moles of neon would be contained in 4.0 L of neon gas at 560 kPa and 127oC

The number of moles present is 68267.08 moles

Explanation:

V = 4.0L

P = 560kPa = 560*10³Pa

T = 127°C = (127 + 273.15)K = 400.15K

Number of moles (n) = ?

R = 0.082J / mol.K

From ideal gas equation,

PV = nRT

n = PV / RT

n = (560*10³ * 4.0) / (0.082 * 400.15)

n = 2240000 / 32.8123

n = 68267.08 moles

The number of moles present is 68267.08 moles

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.