When 40 g of lead reacts with 6.2 g of sulfur, 46.2g of lead sulfide is formed. what mass of lead sulfide is formed when 80 g of lead reacts with 20 g of sulfide?

100 g of lead sulfide is formed.

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

Given : 40 g of lead reacts with 6.2 g of sulfur, 46.2g of lead sulfide is formed.

Thus 80 g of lead reacts with 20 g of sulfide to give 100 g of  lead sulfide  as mass of reactants must be equal to the mass of products.

c. is the answer

by love gaming

the answer is c i took the test