2. Calculate the molarity of a solution if there are 1.5 mol of NaCl in 2.3 L of solution.

0.65 M

Explanation:

Molarity (M) is the amount of moles of a substance per liter.

In other words, M = moles of substance / liters of solution

Since you're already given the moles of NaCl and the volume of the solution, you can plug those into the equation.

M = moles of NaCl / liters of solution

M = 1.5 mol NaCl / 2.3 L

M = 0.65 mol/L (or 0.65 M)

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole