PLZ HELP. How many grams of magnesium(Mg, 24.30 g/mol) are in 7.43×10^22 atoms Mg?

A. (it's on step 2 of my explanation.

Explanation:

I attached a picture for the explanation since i'm assuming you need help understanding how it's solved.

1. since  6.022*10 ^22 atoms of mg is 1 MOLE

2. have to find the moles of mg. so you divide 7.43*10^22 by 6.022*10^22

(you will get .123 moles of mg.

3. to get the mass of Mg, you need to multiply the moles of mg(.123) and the molar mass (amu) of mg (24.30)

Ps. idk y i wrote it out and typed it out. I just felt like i wasn't clear enough on my attached image so... let me know if this helped. (:

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

indium, and thallium have three electrons i think