How much heat energy is added to 29.0 g of copper when the temperature changes by 25 degrees

The correct answer is 3.0 * 10^3 J.

Explanation:

To solve this problem, we must use the formula q = mcΔT, where q represents the heat energy measured in joules, m represents the mass measured in grams, c represents the specific heat measured in J/°C*g, and ΔT represents the change in temperature, measured in °C.

To solve this problem, we must first plug the given values into the equation.

q = mcΔT

q = (29.0 g)(4.184 J/°C*g)(25 °C)

Now, we must multiply the values together to get our final answer.

q = 3033.4 J

But, we must remember the rules of significant figures, which tell us that since the temperature only had 2 significant figures, the answer must have 2 significant figures as well.

Therefore, the answer is:

q = 3.0 * 10^3 J

Hope this helps!

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