What is the concentration of a calcium hydroxide solution, if 35.00 mL of the base is completely neutralized by 12.0 mL of 0.0338 M HCl?

0.00579 M

Explanation:

Concentration of acid CA= 0.0338 M

Volume of acid VA= 12.0mL

Concentration of base CB=

Volume of base VB= 35.00mL

Now we must write the equation of the reaction:

Ca(OH)2(aq) + 2HCl(aq) > CaCl2(aq) + 2H2O(l)

We can now write the number of moles of acid and base

Number of moles of acid NA= 2

Number of moles of base NB= 1

From:

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

CB= CA VA NB/ VB NA

CB=0.0338 × 12.0 × 1/ 35.0 × 2

CB= 0.00579 M