An aqueous solution is 3.23M in tartaric acid (C4H06). The solution's density is 1.023 g/mL.
Calculate the solution's molality in tartaric acid.

Molality = 6.0 m

Explanation:

The molecular weight of tartaric acid = 150.087 g/mol

Given that:

Density  of the solution = 1.023 g/mL

Molarity =  3.23M

Density is given as :

∴

Molality  =

Molality = 5.999 m

Molality ≅ 6.0 m

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer