A mixture of krypton and argon gas is expanded from a volume of 33.0L to a volume of 61.0L , while the pressure is held constant at 58.0atm . Calculate the work done on the gas mixture. Be sure your answer has the correct sign (positive or negative) and the correct number of significant digits.

W = +1624J

Explanation:

V1 = 33.0L

V2 = 61.0L

P = 58 atm

Work = force * distance (∇x)

Work = F.∇x

But force = pressure * area

F = P.A

Work = P.∇x.A

Work = P∇v

Work = P (V₂ - V₁)

Work = 58 * (61 - 33)

Work = 58 * 28

Work = 1624J

The work done is +1624J

answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.