5.54 moles of AgNO3 are dissolved in 0.48 L of water. What is the molarity of the AgNO, solution?

11.54 M

Explanation:

In this case, all we have to do is to apply the following expression:

M = n/V

M: molarity

n: moles

V: volume of solution in liters

In this case, we can assume that the volume of water will be the volume of solution. This is because the problem is not specifing if the moles of AgNO3 are liquid or solid, so we can make a safe assumption of the volume.

Using the expression above we have:

M = 5.54 / 0.48

M = 11.54 M

This is the molarity of solution

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.