CaCl2 (aq) + 2AgNO3 (aq) + Ca(NO3)2 (aq) + 2AGCI (s)

If 25.0 mL of a 2.00 M CaCl2 solution is used for the reaction

shown above, how many moles of chloride ions were involved

in the reaction? — moles

There are 0.100 moles chlorine ions (Cl-) involved

Explanation:

Step 1: Data given

Volume of CaCl2 = 25.0 mL = 0.025 L

Molarity of CaCl2 = 2.00 M

Step 2: The balanced equation

CaCl2 (aq) + 2AgNO3 (aq) ⇆ Ca(NO3)2 (aq) + 2AgCI (s)

CaCl2 → Ca^2+ + 2Cl-

Step 3: Calculate moles CaCl2

Moles CaCl2 = molarity CaCl* volume

Moles CaCl2 = 2.00 M * 0.025 L

Moles CaCl2 = 0.050 moles

Step 4: Calculate moles chloride ions

CaCl2 → Ca^2+ + 2Cl-

For 1 mol CaCl2 we have 1 mol Ca^2+ and 2 moles Cl-

Moles Cl- ions = 2*0.050 moles

Moles Cl- ions = 0.100 moles

There are 0.100 moles chlorine ions (Cl-) involved

in chemistry, adhesion and cohesion are attractive forces that exist between molecules. they hold the molecules together from each other. they are different in that adhesive force exists between molecules of different substance while cohesive force happens between molecules of same substance.

adhesion between water and glass causes water molecules at the edge of water and glass interface to climb up the wall in a narrow glass tube. this is called capillary action. cohesion is what gives glass its shape and causes water to form a droplet.

the answer would be a