Chemistry, 05.05.2020 22:15 winstonbendariovvygn

For this question please enter the number of sigma (σ) and pi (π) bonds (e. g. 0,1,2,3,4, etc). How many sigma and pi bonds, respectively, are in this carboxylic acid? H2CCHCH2COOH. σ bonds and π bond(s). How many sigma and pi bonds, respectively, are in this organic molecule (an amine)? HCCCH2CHCHCH2NH2. σ bonds and π bond(s). How many sigma and pi bonds, respectively, are in this organic molecule (an alcohol)?

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Answer from: ayoismeisjjjjuan

The carboxylic acid has 11 sigma and 2 pi bonds. The amine has 15 sigma bonds and 3 pi bonds.

Sigma bonds are formed by end to end overlap of atomic orbitals while pi bonds are formed by side by side overlap of atomic orbitals. In a sigma bond, the electron density lies along the axis of the bond while in a pi bond, electron density lies above and below the plane of the bond.

In H2CCHCH2COOH, there are 11 sigma and 2 pi bonds. In the compound HCCCH2CHCHCH2NH2, there are 15 sigma bonds and 3 pi bonds.

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For this question please enter the number of sigma (σ) and pi (π) bonds (e.g. 0,1,2,3,4, etc). How m

Answer from: Fireburntbudder

Explanation:

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Answer from: Quest

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Answer from: Quest

assuming that your periodic table has eighteen columns, you should highlight the four elements in the third column from the left of the table.

explanation

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the $3d$ have energy higher than those in the $4 s$ orbital while lower than those of the $4 p$ orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the $4s$ orbital is therefore filled right after $3p$ orbitals and before $3 d$ orbitals.

potassium has electron configuration $[\text{ar}] 4 s^{1}$ and calcium $[\text{ar}] 4 s^{2}$ . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration $[\text{ar}] 4 s^{2} \; 3d^{1}$ and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the $ns^{2} \; (n-1) p^{1}$ and should be highlighted as well.