What is the ph of 0.450 m al(no3)3 [ka for al3+(aq) = 1.00x10-5]? express your answer to two decimal places?

Answer : The pH of the solution is, 2.67

Explanation :

The equilibrium chemical reaction is:

Initial conc.       0.450                   0               0

At eqm.           (0.450-x)                 x               x

As we are given:

The expression for equilibrium constant is:

Now put all the given values in this expression, we get:

The concentration of = x = 0.00212 M

Now we have to calculate the pH of solution.

Therefore, the pH of the solution is, 2.67

i'm assuming that it's c.) red bank..

b is the correct answer

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