How much heat(energy) would be required to raise 20 grams of an unknown substance from 23 degrees Celsius to 33 degrees Celsius

q = 836 J  

Explanation:

The amount of heat required to raise 20 grams of an unknown substance from 23° Celsius to 33° Celsius can be computed below

The specific heat capacity of the substance is not given, so let us assume the specific heat capacity of the substance is 4.18J/g°C.

q = mcΔt

where

q = amount of heat energy

m = mass

c = specific heat capacity

Δt = change in temperature

Δt = 33°C - 23°C = 10°C

q = mcΔt

q = 20 g × 4.18 J/g°C × 10° C

g cancel g and °C cancels °C . We are left with joules

q = 836  J  

why is cellular respiration important for homeostasis?

it changes food into energy that the organism can use.

which of the following is most likely to happen if a cell is not able to divide?

the cell will not be replaced when it is damaged.

explanation:

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i