Titanium(III) chloride, a substance which speeds up the reaction forming polyethylene (a form of plastic), is made by high-temperature reaction of TiCl4 vapor with H2:
2Ti〖Cl〗_(4 ) (g)+ H_2 (g)↔2 Ti〖Cl〗_3 (s)+2HCl(g)
How many grams of TiCl4 are needed for complete reaction with 155L of H2 at 435°C and 795 mm Hg pressure?

1.06 × 10³ g

Explanation:

Let's consider the following reaction

2 TiCl₄(g) + H₂(g) ↔ 2 TiCl₃(s) + 2 HCl(g)

First, we need to calculate the moles of H₂. For that, we need to convert the pressure to atm and the temperature to Kelvin.

Then, we can calculate the moles of H₂ using the ideal gas equation.

The molar ratio of TiCl₄ to H₂ is 2:1. We can use this relation to calculate the moles of TiCl₄.

The molar mass of TiCl₄ is 189.68 g/mol. We will use this data to calculate the mass corresponding to 5.60 moles.

- lead + phosphoric acid = hydrogen + lead(ii) phosphate