A 3.24-gram sample of NaHCO3 was completely decomposed in an experiment.

2NaHCO3 → Na2CO3 + H2CO3

In this experiment, carbon dioxide and water vapors combine to form H2CO3. After decomposition, the Na2CO3 had a mass of 2.19 grams.

Determine the mass of the H2CO3 produced.

Theoretical mass/yield of H2CO3 produced = 1.196 g

Actual mass/yield of  H2CO3 produced = 1.05 g

Explanation:

NaHCO3 sample was decomposed to  Na2CO3 + H2CO3. The balanced chemical equation for the reaction is represented below:

2NaHCO3 → Na2CO3 + H2CO3

The mass of NaHCO3 = 3.24 g

Molar mass of NaHCO3  = 23 + 1 + 12 + 48 = 84 g

From the chemical equation 2 moles of NaHCO3 was used. Therefore the mass will be 2 × 84 = 168 g

Molar mass of H2CO3 = 2 + 12 + 48 = 62 g

168 g of  NaHCO3 produces 62 g of H2CO3

3.24 g of NaHCO3 will produce ? g of H2CO3

cross multiply

theoretical mass of H2CO3 produced = (3.24 × 62)/168

theoretical mass of H2CO3 produced = 200.88/168

theoretical mass of H2CO3 produced = 1.1957142857 g

Theoretical mass of H2CO3 produced = 1.196 g

Actual mass of H2CO3

Actual mass of  H2CO3 produced = mass of NaHCO3 - mass of  Na2CO3

Actual mass of  H2CO3 produced = 3.24 - 2.19

Actual mass of  H2CO3 produced = 1.05 g

The question didn't indicate whether you want the actual mass or theoretical mass but i calculated for both mass.

answer

fusion: the energy source of stars. the energy released from the collapse of the gas into a protostar causes the center of the protostar to become extremely hot. when the core is hot enough, nuclear fusion commences. fusion is the process where two hydrogen atoms combine to form a helium atom, releasing energy.

hope it

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.