Gaseous ammonia chemically reacts with oxygen o2 gas to produce nitrogen monoxide gas and water vapor. Calculate the moles of nitrogen monoxide produced by the reaction of 0.050mol of ammonia . Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.

0.050 moles of nitrogen monoxide are produced by 0.050 moles of ammonia.

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced chemical reaction is:

According to stoichiometry:

4 moles of ammonia produce = 4 moles of nitrogen monoxide

Thus 0.050 moles of ammonia produce = moles of nitrogen monoxide

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%