A weather balloon is filled to a volume of 7880 L at 525 mm Hg and 19°C. When the balloon is released, it rises to an altitude where the pressure and temperature are 339 mm Hg and -55oC, respectively. What is the volume of the balloon (in L)?

The answer to your question is V2 = 9110.86 l

Explanation:

Data

Volume 1 = V1 = 7880 l

Pressure 1 = P1 = 525 mmHg

Temperature 1 = T1 = 19°C

Volume 2 = V2 = ?

Pressure 2 = P2 = 339 mmHg

Temperature 2 = T2 = -55°C

Process

1.- Convert temperature to °K

T1 = 19 + 273 = 292°K

T2 = -55 + 273 = 218°K

2.- Use the combined gas law to solve this problem

                 P1V1/T1 = P2V2/T2

-Solve for V2

                  V2 = P1V1T2 / T1P2

-Substitution

                 V2 = (525 x 7880 x 218) / (292 x 339)

-Simplification

                  V2 = 901866000 / 98988

-Result

                   V2 = 9110.86 l

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6

< > according to newton's third law of motion, forces always act in equal but opposite pairs. another way of saying this is for every action, there is an equal but opposite reaction.< >