Chemistry, 25.04.2020 03:50 abadir2008

Use the specific heat capacity that you calculated for granite to determine how many grams of granite at the initial temperature of 80 °C must mix with 3,000 g of water at the initial temperature of 20 °C to result in a final system temperature of 20.45 °X. (Hunt: Start by calculating how much heat energy is needed to change the water’s temperature by 0.45 °C). Show your work. Use the Gizmo to check your answer.

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Answer from: syulerio8418

Explanation:

specific heat of granite s = .79 J / g / k

let the mass of granite = m

heat lost by granite = heat gained by water

heat lost = mass x specific heat x drop in temperature

= m x .79 x (80 - 20.45)

heat gained by water

= 3000 x 4.186 x (20.45- 20)

heat lost by granite = heat gained by water

m x .79 x 59.55 = 3000 x 4.186 x .45

m = 120.12 g .

Answer from: jonystroyer1020

The mass of granite is approximately equal to 120 g.

The specific heat capacity refers to the amount of energy required or needed to raise the temperature of 1 gram of a material or substance by 1° C.

Let assume that:

the mass of the water is 1000 g at 2.93 °C

The heat energy gained by water can be calculated using the formula:

Q = mcΔT

where;

m = mass = 1000 g

c = specific heat = 4.183 J/g° C

ΔT = change in temperature

Q = 1000 g × 4.183 J/g° C × (2.93 - 0)° C

Q = 1000 g × 4.183 J/g° C × (2.93) ° C

Q = 12256.19 J

Q = 12.256 kJ

The next step is to determine the specific heat of granite.

Since;

The heat gained by water = Heat lost by granite.

The heat lost by granite = 12.256 kJ

Using the relation;

Q = mcΔT

Making (c) the subject of the formula:

$\mathbf{c = \dfrac{Q}{m \Delta T}}$

$\mathbf{c = \dfrac{12.256 \ kJ}{200 \times (100 - 22.93)^0 \ C}}$

$\mathbf{c = \dfrac{12.256 \times 10^3 \ J}{200 \ g \times (77.07)^0 \ C}}$

$\mathbf{c = 0.795 \ J/g^0 \ C }$

The specific heat of granite = 0.795 J/g° C

Recall from the given parameters;

initial temperature of granite = 80°Cinitial temperature of water = 20°C

∴

Again, heat gained by water = heat lost by granite

$\mathbf{m_{water} \times c_{water} \times \Delta T= m_{granite} \times c_{granite} \times \Delta T}$

To determine the mass of granite, make $\mathbf{m_{granite} }$ the subject of the formula;

i.e.

$\mathbf{ m_{granite}= \dfrac{m_{water} \times c_{water} \times \Delta T}{c_{granite} \times \Delta T} }$

$\mathbf{ m_{granite}= \dfrac{3000 g \times 4.184 \ J/g^0 \ C \times (20.45 - 20)^0 \ C}{0.795 J/g^0 \ C \times(80-20.45)^0 \ C} }$

$\mathbf{ m_{granite}= \dfrac{5648.4 g}{47.34225} }$

$\mathbf{ m_{granite}=119.31 \ g }$

Therefore, we can conclude that the mass of granite is approximately equal to 120 g.

Learn more about specific heat capacity here:

link

Answer from: Quest

n2(g) + 3h2-> 2nh3(g) this is the balanced equation

note the mole ratio between n2, h2 and nh3. it is 1 : 3 : 2 this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note: the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.

Answer from: Quest

space exploration has led to the development and technological improvement of many everyday items. (if this answer is wrong i will find the right answer) : )

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Use the specific heat capacity that you calculated for granite to determine how many grams of granit...