For the reaction Ag2S(s) ⇌ 2Ag+(aq) + S2−(aq), what happens to the equilibrium position if the amount of silver ion is halved?For the reaction S(s) ⇌ 2(aq) + (aq), what happens to the equilibrium position if the amount of silver ion is halved?

More silver and sulfide ions will be yielded as the reaction proceeds.

Explanation:

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In this case, with the given reaction at equilibrium:

We take into account the Le Chatelier's principle in order to explain what would happen when the amount of solver ion is halved. Thus, it explains that when the amount of one product is diminished as in this case, since by halving its amount is reduced to the half, the direct reaction is favored (reaction will shift rightwards), it means the formation of products, so more silver and sulfide ions will be yielded as the reaction proceeds.

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hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.