The pressure in a 100ml container is 150.2 kpa at 500k. that pressure is adjusted to 101.3kpa, what is the new temperature

The new temperature is 337.21 K when the pressure was reduced to 101.3 kPa from 150.2 kPa at 500 K.

Explanation:

Data given:

volume of the container = 100 ml

initial pressure on the container P1 = 150.2 kPa

Initial temperature of the container, T1 = 500 K

final temperature of the container, T2 = ?

Final pressure on the container P2 = 101.3 kPa

from the data provided, we will use Gay Lussac's law to calculate the final temperature:

rearranging the equation,

T2 =

Putting the values in the equation:

T2 =

T2 = 337.21 K

thus, the final temperature of the container is 337.21 K

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.

a:

by the combination of an unlimited number of elements