If exactly 59.6 g of nitrogen gas is needed to inflate your air bag to the
correct size, how many grams of sodium azide would you need to
decompose? *

We need 92.3 grams of sodium azide

Explanation:

Step 1: Data given

Mass of nitrogen gas = 59.6 grams

Molar mass of nitrogen gas = 28.0 g/mol

Molar mass of sodium azide = 65.0 g/mol

Step 2: The balanced equation

2NaN3 → 2Na + 3N2

Step 3: Calculate moles nitrogen gas

Moles N2 = mass N2 / molar mass N2

Moles N2 = 59.6 grams/ 28.0 g/mol

Moles N2 = 2.13 moles

Step 4: Calculate moles NaN3

for 2 moles NaN3 we'll have 2 moles Na and 3  moles N2

For 2.13 moles N2 we need 2/3* 2.13 = 1.42 moles NaN3

Step 5: Calculate mass NaN3

Mass NaN3 = Moles NaN3 * molar mass NaN3

Mass NaN3 = 1.42 moles * 65.0 g/mol

Mass NaN3 = 92.3 grams

We need 92.3 grams of sodium azide

chemistry sucks a**

explanation: