A gas has a volume of 1.4 liters at STP. What is the new volume when the temperature is changed
to 40 K and the pressure is changed to 1.2 atm?

Answer : The new volume when the temperature is changed  to 40 K and the pressure is changed to 1.2 atm is, 0.17 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

where,

= initial pressure of gas at STP  = 1 atm

= final pressure of gas = 1.2 atm

= initial volume of gas at STP = 1.4 L

= final volume of gas = ?

= initial temperature of gas at STP = 273 K

= final temperature of gas = 40 K

Now put all the given values in the above equation, we get:

Therefore, the new volume when the temperature is changed  to 40 K and the pressure is changed to 1.2 atm is, 0.17 L

why do the isotopes of a particular element behave differently in nuclear reactions but the same in chemical reactions? chemical reactions involve changes to electrons in an atom; isotopes do not differ in electrons, and so they react the same way during chemical changes.

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).