Calculate delta s ,delta s total when the volume of 123 g CO initially at 298K and 1 bar increased by a factor of four in (a) an adiabatic reversible expansion

0

Explanation:

we have ,

T = 298K temperature

P = 1.00 bar. pressure

M = 123g. mass CO

a) Adiabatic reversible expansion

q= 0. Heat is zero

we know the total entropy change is

ΔS total = Δs + Δs surrounding

ΔS surrounding = -q/ T

So, ΔS surrounding= 0

in reversible process,

ΔS= 0

Change in entropy should be positive for spontaneous process ΔS total ≥0

Therefore,

ΔS total= ΔS + ΔS surrounding

= 0

Hence, we can say that the process is not spontaneous, so the system and surrounding are in equilibrium.  

icc, international association for cereal chemistry

odds are decent that your handwriting right now looks a little bit different than it did five years ago, and will look different again in five more. when i look back through my notebooks from middle school to now, i see a long, slow progression from meticulous and teeny letters to bigger, sloppier ones, plus a few side detours: sometime in high school, for example, i decided those loopy cursive lowercase f’s were just the coolest, adopting them as the lone rep for cursive in my otherwise all-print handwriting.

explanation: