A cylinder of O2 gas occupies a volume of 60.50 L at STP. How many moles of oxygen

gas are in the cylinder?

The answer to your question is 2.52 moles

Explanation:

Data

Volume = 60.5 l

Temperature = 20°C

Pressure = 1 atm

Constant of ideal gases = R = 0.082 atm l/mol°K

Formula

PV = nRT

-Solve for n

   n = PV / RT

-Convert temperature to °K

Temperature = 20 + 273

                      = 293°K

-Substitution

   n = (1 x 60.5) / (0.082 x 293)

-Simplification

    n = 60.5 / 24.026

-Result

    n = 2.52 moles

the ratio of the conjugate base to the acid required to attain the desired ph.