Choose a likely identity for X, Y, and Z in these structures. A central X atom is bonded to two chlorine atoms through single bonds. There are three lone pairs of electrons on each chlorine atom. C Be B F O N A central Y atom is bonded to three chlorine atoms through single bonds. There are three lone pairs of electrons on each chlorine atom. A central Z atom is bonded to two chlorine atoms through single bonds. There are three lone pairs of electrons on each chlorine atom and two lone pairs of electrons on the Z atom. Be C N B F O C Be B O N F

The identity for X, Y, and Z in the structures that are given will be

X = Be, Y= B, and Z = O

It should be noted that from the description of the compound that is given, only beryllium can form a compound that has three lone pairs in the two chlorine atoms and no lone pair on the central atom X.

For the second compound given, only Boron can form such a compound that will have no lone pair on the central atom while it has three lone pairs on each of the chlorine atoms.

For the last compound, it can be deduced that only oxygen forms the compound given such that oxygen has two lone pairs and each chlorine atom has three lone pairs each.

In conclusion, the identity for X, Y, and Z in the structures that are given will be X = Be, Y= B, and Z = O.

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X= Be

Y= B

Z=O

Explanation:

From the description of the compound XCl2, among the options listed only beryllium can form such compound with three lone pairs in the two chlorine atoms and no lone pair on the central atom X.

From the description of YCl3, only Boron among the options listed can form such a compound with no lone pair on the central atom and three lone pairs on each of the chlorine atoms.

From the description of ZCl2, only oxygen forms the compound OCl2 among the elements listed where oxygen possesses two lone pairs and each chlorine atom possesses three lone pairs each.

it takes on an electronical energy