Determine the specific heat of a material if a 35-9 sample absorbed 96 ) as it was heated from 293 Kto 313 K.

This is an incomplete question, here is a complete question.

Determine the specific heat of a material if a 35 g sample absorbed 96 J as it was heated from 293 K to 313 K.

Answer : The specific heat of a material is, 0.137 J/g.K

Explanation :

Formula used to calculate the specific heat of a material is:

where,

q = heat absorbed = 96 J

m = mass of sample = 35 g

c = specific heat capacity of material = ?

= initial temperature = 293 K

= final temperature = 313 K

Now put all the given values in the above formula, we get:

Therefore, the specific heat of a material is, 0.137 J/g.K