For the balanced equation shown below, if the reaction of 0.112 grams of

H2 produces 0.745 grams of H20, what is the percent yield? Fe3O4 + 4H2 -> 3Fe

+ 4H2O

74.5%

84.5%

94.5%

092.2%

The answer is 74.5%.

Explanation:

As we know that % yield=   x 100%.

Therefore,

Step 1 Calculate Theoretical yield:

0.112 x      x        x     = 1.001 g

Now Step 2

% yield   =   x 100% =   = 74.5%

given the reactants, h2so4 and koh, we are asked to determine the product(s) of the reaction. since h2so4 is an acid and koh is a base. this is a neutralization reaction, thus, the products are salt and water. 

so, h+ from h2so4 will react with oh- from koh forming h2o. k+ will also react with so4 2- forming k2so4. therefore, the balanced reaction will be:

h2so4 + 2koh > k2so4 + 2h2o

explanation: